Question

A force of 200 Newton acts on a body of mass 40 kg for 4 seconds,initially at rest. Calculate the :(a) velocity acquired by the body (b) change in momentum of the body​

Answer 1

F = 200N

m = 40kg

t = 4s

u = 0

v = ?

F = ma

a = F/m = 200/40 = 5m/s²

v = u + at

v = 0 + 5×4

v = 20m/s

Initial momentum = mu = 40×0 = 0

Final momentum = mv = 40×20 = 800kg m/s

Therefore,

change in momentum = final - initial momentum

= 800-0 = 800 kg m/s

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