Question

A force of 200N acts on a body of mass 20kg initially rest for 5 seconds. Determine i) acceleration ii) final velocity attained and iii) distance covered by it

Answer 1

Answer:

f =ma

200= 20×a

a= 10

v=u+at

v=0 +10×5

v=50

s=ut +1/2at square

s=0+1/2×10×5

s=5×5

s=25