Question

A force of 200N acts on a body of mass 20kg initially rest for 5 seconds Determine 1) acceleration 2) final velocity attained and 3) distance covered by it

Answer 1

Answer:

1) a=10. 2) V=50. 3) S=2.5

Explanation:

1) force = mass × acceleration

200=20×a

a=200÷20

a=10

2)v=u+at

v=0+10×5. (body is at rest)

v=50.

3)v=u+2aS

50=0+2×10×S

50=20×S

S=50÷20

S=5÷2

S=2.5