Question

A force of 200n is applied to an object of an area 2
metre square calculate the pressure

Answer 1

☯ GiveN :

Force applied by the object = 200 N

Area = 2 m²

$\rule{200}{1}$

☯ To FinD :

We have to find the pressure applied ?

$\rule{200}{1}$

☯ SolutioN :

We know the formula to calculate the pressure.

$\Large{\implies{\boxed{\boxed{\sf{Pressure = \dfrac{Force}{Area}}}}}}$

★ Putting Values ★

$\sf{\dashrightarrow Pressure = \dfrac{\cancel{200}}{\cancel{2}}} \\ \\ \sf{\dashrightarrow Pressure = 100 \: Nm^{-2}} \\ \\ \Large{\implies{\boxed{\boxed{\sf{Pressure = 100 \: Pascal}}}}}$

Answer 2

Answer :-

$\boxed{ \sf{ p = 100 \: \frac{N}{ {m}^{2} \:}or \: pascal }} \: \:$

To Find :-

→ Pressure

Explanation :-

Given that :

• Force (F) = 200 N

• area = 2 m²

• pressure (p) = ?

We know that ;

$\implies \sf{ pressure \: (p) = \frac{force}{area} } \\ \\ \implies \sf{ p = \frac{200}{2} } \\ \\ \implies \: \boxed{ \sf{ p = 100 \: \frac{N}{ {m}^{2} \:}or \: pascal }} \:$

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Other important formula ;-

$(1) \sf{ force =mass \times acceleration} \\ \\ (2) \sf{ power = \frac{work}{time} } \\ \\ (3) \sf{ kinetic \: energy = \frac{1}{2} m \: {v}^{2} } \\ \\ (4) \sf{potential \: energy = mgh \:} \\ \\ (5) \sf{spring \: potential \: enegy} \\ \: \: \: \: \: \: \: \: \sf{ = \frac{k}{2} \big( {x_{(final)} }^{2} - {x_{(initial)} }^{2} \big)}$