Question

a force of 200N is required to push a car of mass 500 kg slowly at constant speed on a level road. If a force of 500N is applied ,the acceleration of the car (in m per second) will ve

Answer 1

If 500N is applied, it means that the excess force ie 500-200= 300N will provide the acceleration!

Therefore by the formula F=ma. we have 300=500*a which gives a= 3/5 m/s/s where a is acceleration..

OR a= 0.6 meters per second square(m/s/s)

Answer 2

Answer:

Explanation:

Concept:

According to Newton's second law, an object's acceleration is determined by its mass and the net force that is acting on it. The body's acceleration is inversely related to its mass and directly proportional to the net force acting on it. This implies that as the force applied on an item increases, so does the object's acceleration. Similar to how an object's acceleration decreases as its mass increases, so does its mass.

The formal formulation of Newton's second law is

A net force's ability to accelerate an item is directly proportional to the force's strength, in the same direction as the force, and inversely proportional to the mass of the object.

This statement is expressed in equation form as,

$F_{net} =ma$

Given:

The force of friction from the road is $200 N$

Mass of car is $500 kg$

Now, the force applied (F) is $500 N$

Find:

To find the the acceleration of the car.

Solution:

The car moves continuously when $200 N$ of force is given to it.

According to Newton's second law:

$F_{net} =ma$

$Force applied - Friction = ma\\500 - 200 = 500 \times a\\a=\frac{300}{500} \\a=0.6m/s^{2}$

Therefore, the acceleration of the car is $0.6 m/s^2$.

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