Question

a force of 20N acts on a body of 2kg for 3 seconds .find the kinetic energy in 3 seconds.


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Flw : @MissNalayak ​

Answer 1

Answer:

Kinetic energy = 900

Explanation:

As given in the question

Body mass = 2 Kg

Force acting on body = 20N

Time interval = 3 sec

Let, m denotes mass of body

v denotes final velocity of body

F denotes Force acting on body

t denotes time interval of body

u denotes initial velocity of body

a denotes acceleration of body

KE denotes Kinetic Energy of body

So we know,

KE = 1/2 mv^2

But here v (velocity) is not given so firstly we find v, To find v we use

v = u + a×t ...(1)

But we dont know a also so by

F = m×a

=> a = F/m

=> a = 20 / 2

=> a = 10

Value of a put it in eq(1) to find v

v = u + a×t

=> v = 0 + 10×3 (as initially u=0 and t = 3 )

=> v = 30 m/s

Now Putting the value of v in KE formula we get

KE = 1/2 ×m×v^2

= 1/2 ×2×(30)^2

= 30^2

= 900 J

Thankyou,

Answered by

Aaditya Singh

Answer 2

Answer:

Kinetic energy = 900

Explanation:

As given in the question

Body mass = 2 Kg

Force acting on body = 20N

Time interval = 3 sec

Let, m denotes mass of body

v denotes final velocity of body

F denotes Force acting on body

t denotes time interval of body

u denotes initial velocity of body

a denotes acceleration of body

KE denotes Kinetic Energy of body

So we know,

KE = 1/2 mv^2

But here v (velocity) is not given so firstly we find v, To find v we use

v = u + a×t ...(1)

But we dont know a also so by

F = m×a

=> a = F/m

=> a = 20 / 2

=> a = 10

Value of a put it in eq(1) to find v

v = u + a×t

=> v = 0 + 10×3 (as initially u=0 and t = 3 )

=> v = 30 m/s

Now Putting the value of v in KE formula we get

KE = 1/2 ×m×v^2

= 1/2 ×2×(30)^2

= 30^2

= 900 J

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