Question

a force of 20n acts on a body of mass 0.5kg . find the acceleration of the particles. ​

Answer 1

Answer:

force = mass×acceleration

20n=0.5×a

a=20/0.5

a=40

therefore acceleration of particles is 40m/s²

Answer 2

Answer:

(a) The acceleration of the particle is

     a=  

m

F

​  

=  

0.5kg

2.0N

​  

=4.0m/s  

2

.

The distance moved by the particle in 5.0s is

      s=ut+  

2

1

​  

at  

2

=0+  

2

1

​  

×(4.0m/s  

2

)×(5s)  

2

=50m.

(b) The velocity at the end of the first 5.0s is

      v=u+at=0+(4.0m/s  

2

)×(5.0s)=20m/s.

After this, the force is withdrawn, and hence, the particle moves with uniform velocity. The distance moved in the next 5.0s is,

      s=ut=(20m/s)×(5.0s)=100m.

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