a force of 20n acts on a body of mass 0.5kg . find the acceleration of the particles.
Answers
Answered by
1
Answer:
force = mass×acceleration
20n=0.5×a
a=20/0.5
a=40
therefore acceleration of particles is 40m/s²
Answered by
0
Answer:
(a) The acceleration of the particle is
a=
m
F
=
0.5kg
2.0N
=4.0m/s
2
.
The distance moved by the particle in 5.0s is
s=ut+
2
1
at
2
=0+
2
1
×(4.0m/s
2
)×(5s)
2
=50m.
(b) The velocity at the end of the first 5.0s is
v=u+at=0+(4.0m/s
2
)×(5.0s)=20m/s.
After this, the force is withdrawn, and hence, the particle moves with uniform velocity. The distance moved in the next 5.0s is,
s=ut=(20m/s)×(5.0s)=100m.
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