A force of 20N acts on a mass of 2kg and displaces it by 5m at an angle of 30 degree . What is the workdone?
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Answered by
10
Hey dearie
Work done = Fscostheta
Where f is force
S is displacement
Putting values
Work done = 20*5*root3/2
=50root3joule
Hope it helps uh
Work done = Fscostheta
Where f is force
S is displacement
Putting values
Work done = 20*5*root3/2
=50root3joule
Hope it helps uh
Answered by
0
work done = force× distance
=10√3×5
= 50√3 NM
=10√3×5
= 50√3 NM
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