A force of 20n applied parallel to d surface of a horizontal table is just sufficient to make a block of mass 4kg move on d table what is d co,efficient of friction between d surfacf of d block and d table .
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Explanation:
Given:
Force applied on the block is F = 20 N.
Mass of the block is m = 4 kg.
The weight of the block is {eq}W = mg = 4 \times 9.8 \ N = 39.2 \...
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