Question

A force of 20N applied parallel to the surface of a horizontal table is just sufficient to make a block of mass 4kg move on the table. calculate the coefficient of friction between the block and the table.(gram:10)

please I would be so glad and happy if this is done and correct

Answer 1

Answer:

A horizontal force of 20 N is applied to a block of mass 4 kg resting on a rough horizontal table. What can be said about the coefficient of static friction between the block and the table if the block remains at rest? [g=10 ms

−2

]

Answer 2

Answer:

Explanation:

Here frictional force =applied force

u mg = 20

u =20/4(10)

u =1/2=0.5