Question

a force of 20N displaces a body through a distance of 1m at an angle of 60degree from its own direction. calculate the amount of work done.​

Answer 1

Force = 20N

Displacement = 1m

∅ = 60°

Work Done = Fscos∅

=>20×1×cos60°

=>20×1/2

=>10J

Cheers!

Answer 2

The amount of work done by the force is 10 J.

Explanation:

It is given that,

Force, F = 20 N

Distance, d = 1 m

Angle with horizontal, $\theta=60^{\circ}$

Let W is the amount of work done. It is given by :

$W=Fd\ cos\theta$

$W=20\times 1\ cos(60)$

W = 10 J

So, the amount of work done by the force is 10 J. Hence, this is the required solution.

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