a force of 20n is acting on a body of mass 10kg is found to double it's velocity in 10s. find it's initial velocity
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Answer:
f=ma
a=f/m
a=20/10
a=2m/s²
let v=2x,u=x
a=(v-u)/t
2m/s²= (2x-x)/10s
2m/s²×10s=x
20m/s=x
therefore u=20m/s
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