Question

a force of 20N is appliedon anail, whose area of cross section is 0.01cm^2. What is the pressure on the nail?

Answer 1

Hey mate...here is ur ans...✌❤❤

✔Pressure = thrust / area

✔Thrust = 20 N

✔Area = 0.01 cm^2 = ( 0.01 / 100 × 0.01 / 100 ) m

= 1 × 1 / 100 × 100

✔P = ( 20 / 1/100 × 1/100 × 100) Pa

✔P = 20 × 10 ^6 pascal

Hope it helps u..thanks...✌❤❤

Answer 2

$\huge\orange{As-Salamu-Alykum}$


__________

$\huge\pink{Given :- }$



Force = 20N


Area = 0.01cm^2



(1cm)^2 = (1/100)^2



0.01cm^2= (1/100m)^2 ×0.01


0.01cm^2 = 1/10^4 ×0.01



0.01cm^2 = 10^_6m^2


Pressure = ??



$\huge\green{Solution :- }$


P=F/A


P =20/10^_6


P =20×10^6 Pascal


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$\huge\purple{INSHALLAH it will help U}$