Question

a force of 20N is inclined at 30 degrees to the x-axis calculate the x and y component

Answer 1

X component will be,
$= (20) \cos(30$°)

$= (20)(\frac{\sqrt{3} }{2})$

$= 10 \sqrt{3}$

And Y component will be,
$= (20) \sin(30$°)

$= (20)(\frac{1}{2})$

$= 10$

Answer 2

f=fcos 30'
$f = 20 \times \cos(30) \\ f = 20 \times \sqrt{3 } \div 2 \\ f = 10 \times \sqrt{3 } \\ f = 17.1 \: in \: x \: component$
$f = f \times \sin(30) \\ f = 20 \times 1 \div 2 \\ f = 10 \: in \: y \: component$