Question

A Force of 20N is uniformly distributed over a
rectangular table of dimension 1m*0.5 m, Calculate
the pressure exerted on the table. (hint: direct formula can be used.)​

Answer 1

Answer:

40 pascal

Explanation:

20N/0.5m^2=200/5=40Pa

Answer 2

Question :-

A force of 20 N is uniformly distributed over a  rectangular table of dimension $\sf{1\ m\times0.5\ m.}$ Calculate  the pressure exerted on the table.

Answer:-

$\Large\boxed{\ \sf{40\ Pa}\ }$

Solution:-

Force, $\sf{F=20\ N.}$

Area, $\sf{A=1\times0.5=0.5\ m^2.}$

We have, pressure,

$\longrightarrow\sf{P=\dfrac{F}{A}}$

$\longrightarrow\sf{P=\dfrac{20\ N}{0.5\ m^2}}$

$\longrightarrow\sf{\underline{\underline{P=40\ Pa}}}$