Question

A force of 20N passes through points A(1,2) and B(2,1). The moment of the force

about the origin will be nearer to​

Answer 1

Answer:

42Nm

Step-by-step explanation:

Answer 2

Answer : The moment of force is 20√2 or 28.28 Step-by-step Explanation : Given : Force ( F ) = 20N Coordinates of A = ( 1 , 2 ) Coordinates of B = ( 2 , 1 ) To find : moment of the force about the origin = ? We know that, Moment of force = Force × distance ------ (1) But, A(1,2) and B(2,1) --------- (given) So, position vector AB = ( 2-1 , 1-2 ) = ( 1 , -1 ) We know that, Magnitude of position vector AB = √ x² + y² = √ 1 + 1 = √2 Substituting the value in Equation 1 we get Moment of force = 20 × √2 = 20√2 or 20 × 1.414 = 20√2 or 28.28 Hence the moment of force is 20√2 or 28.28