A force of 24 N acting on a body of mass 6kg
Answers
Answered by
0
Answer:
Given,
m=6 kg
μ
s
= 0.2
F= 12 N
Maximum static frictional force acting on the body =μ
s
mg=0.2(6)(10)=12N.
Since the applied force (10N) is less than the maximum static frictional force, the body won't move (zero acceleration) and the static frictional force adjusts to 10 N.
Answered by
0
Explanation:
According to the given question,
m=mass=6 kg
a=acceleration=4 m/s^2
F=force=?
We know from Newton's second law,
.F=4×6
.F=24 N.
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