Question

A force of 24 N acts on a body of mass 6 kg for 4 s. Assuming the body to be initially at rest. Then (A) When the force stops acting its velocity is 16 m/s (B) The distance covered in 10 s after the force acting is 128 m (C) The distance covered in 5 s after the force stops acting is 96 m (D) Its momentum after 10 s is 96 kg ms-1, The correct option(s) is/are Only B Only A Both (B) and (D)​

Answer 1

Answer:

correct option is C

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Answer 2

Answer: (A) When the force stops acting its velocity is 16 m/s

               (D) Its momentum after 10 s is 96 $kg.m/s$.

Explanation:

• We know whenever a force acts on a body then its changes the state of the object.
• The basic formulae of force is F=ma.
• Where F is the force, m is the mass of the body and a is the acceleration produced.
• We also know acceleration is defined as the change in velocity per unit time i.e., a=$\frac{v}{t}$.
• Now, in  F=$m\frac{v}{t}$  putting the value of F, m and t.

                  ⇒ 24=$6\frac{v}{4}$

                  ⇒ v = 16 m/s

      And a= 4 $m/s^{2}$

               $S=ut+\frac{1}{2}at^{2}$

                   = 0 + 200

                   = 200 m

             P= mv

               = 6*16

               = 96 $kg.m/s$

• We can see clearly that options are A and D.
• Hence, the required answer is both A and D.

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