A force of 25 N acting on a rigid body produces a moment of force 10 Nm. Determine the perpendicular distance between the point of application of force and the turning point.
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F = 50N Moment of force =10Nm ⊥ distance = ? Moment of force = F × ⊥ dist. 10 = 50 × ⊥ distance. ∴ ⊥ distance 10/50 = 0.2mRead more on Sarthaks.com - https://www.sarthaks.com/276536/a-force-of-50n-produces-a-moment-of-force-of-10nm-in-a-rigid-body
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