Question

A force of 25 N acts on a body of mass 5 kg and produces a displacement of 5 m in its own
direction. Calculate the amount of work done.
​

Answer 1

Step-by-step explanation:

Force, F=10N

Mass, m=5Kg

Force,

F=ma

a=2m/s

2

Work done, W=F.ds

In first second, displacement,

s=

2

1

at

2

s=

2

1

×2×1

s=1m

So, work done,W=10×1=10J

In second second, s=

2

1

×2×4=4m

So, the displacement is , 4−1=3m

Hence, work done in 2 second is,

W=10×3

W=30J

Answer 2

Answer:

125 joule

25 N ×5kg.

5m+5kg. =. 25

25×25=625

625/25

= 125 J