Question

A force of 25 newton is applied on an object of mass 10 kg moving with a velocity of 5 ms⁻¹. If the object gains a velocity of 10 ms⁻¹ , calculate the time taken.

Answer 1

HELLO MATE


YOUR ANSWER
WITH SOLUTION




F=25N
m=10kg
u=5m/s
v=10m/s


F=ma
F=m(v-u)/t
25=10(10-5)/t
25t=10×2
25t=20
t=20/25
t=4/5
t=0.8second




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Answer 2

No Hi mate.

Thanks for asking this question.

Here Here is your answer,




Given :

F = 25 N.

M = 10 Kg.

V = 10 m/s.

U = 5 m/s.




We know that,


$force \: = mass \times acceleration$


$f = m \times a...........................(1)$

But,

We also know that,


$a \: = \frac{dv}{t}$

$a = \frac{v - u}{t}$

$a = \frac{10 - 5}{t} = \frac{5}{t}$

Put, this value in equation (1),
We get,


$f = m \times \frac{5}{t}$

$25 = 10 \times \frac{5}{t}$

$t = \frac{50}{25}$


$t \: = 2 \: sec.$






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