Question

a force of 250 Newton produces a moment of force of 500Nm calculate the moment arm​

Answer 1

Explanation:

Force = 250 N

Force = 250 NMoment of force or Torque = 500 Nm

Force = 250 NMoment of force or Torque = 500 NmLet the moment of arm be r, which is the perpendicular distance from the axis of rotation to the point of application of the force.

Force = 250 NMoment of force or Torque = 500 NmLet the moment of arm be r, which is the perpendicular distance from the axis of rotation to the point of application of the force.Given that:

Force = 250 NMoment of force or Torque = 500 NmLet the moment of arm be r, which is the perpendicular distance from the axis of rotation to the point of application of the force.Given that:A 250 N force is producing a torque of 500 Nm.

Force = 250 NMoment of force or Torque = 500 NmLet the moment of arm be r, which is the perpendicular distance from the axis of rotation to the point of application of the force.Given that:A 250 N force is producing a torque of 500 Nm.Formula to be used:

Force = 250 NMoment of force or Torque = 500 NmLet the moment of arm be r, which is the perpendicular distance from the axis of rotation to the point of application of the force.Given that:A 250 N force is producing a torque of 500 Nm.Formula to be used:Torque = r × F

Force = 250 NMoment of force or Torque = 500 NmLet the moment of arm be r, which is the perpendicular distance from the axis of rotation to the point of application of the force.Given that:A 250 N force is producing a torque of 500 Nm.Formula to be used:Torque = r × F\( r = \frac{Torque}{Force}\)

Force = 250 NMoment of force or Torque = 500 NmLet the moment of arm be r, which is the perpendicular distance from the axis of rotation to the point of application of the force.Given that:A 250 N force is producing a torque of 500 Nm.Formula to be used:Torque = r × F\( r = \frac{Torque}{Force}\)\(r = \frac{500}{250}\)

Force = 250 NMoment of force or Torque = 500 NmLet the moment of arm be r, which is the perpendicular distance from the axis of rotation to the point of application of the force.Given that:A 250 N force is producing a torque of 500 Nm.Formula to be used:Torque = r × F\( r = \frac{Torque}{Force}\)\(r = \frac{500}{250}\)r = 2 m

Force = 250 NMoment of force or Torque = 500 NmLet the moment of arm be r, which is the perpendicular distance from the axis of rotation to the point of application of the force.Given that:A 250 N force is producing a torque of 500 Nm.Formula to be used:Torque = r × F\( r = \frac{Torque}{Force}\)\(r = \frac{500}{250}\)r = 2 mHence, the moment of arm is 2 meters

Answer 2

define moment of a force write its SI unit