Question

A force of 25N acting on a rigid body produces a moment of force 10Nm.Dtermine the pendicular distance between the point of application of force and turning point.

Answer 1

Answer:

your answer is ---

moment = force × perpendicular distance

=> moment = 200 × 0.5

=> moment = 100 Nm

hope this helps you!

Explanation:

Answer 2

Answer:

The perpendicular distance between the point of application of force and turning point = 0.4m

Explanation:

Torque:

• Torque is defined as the product of force and the perpendicular distance between the point of application of force and the pivot/turning point.

Given force |F| = 25N

  moment of force = torque = |τ| = 10Nm

   angle θ = 90°

   We need to find the Perpendicular distance |d|

We know that

    Torque = cross product of distance and the moment of force.

       |τ| = |d| x |F|

       |τ| = |d| |F| sinθ

       |d| = |τ|/(|F| sinθ)

    since θ = 90° , sin90°=1 , |τ| = 10Nm, |F| = 25N

       substitute all the values then we get

        |d| = |τ|/|F|

        |d| = 10/25

        |d| = 0.4m

      Hence the perpendicular distance = 0.4m

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