A force of 25N acts on a body at rest for 0.2s and a force of 70 N acts for the next 0.1 s in opposite direction. If the final velocity of the body is 5m/s, the mass of the body is
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Answered by
281
Let the mass of the body be m.
Case:1
Force of 25N acts on the body for 0.2s
We know that F=ma
F=ma
F=m[(v-u)/t]
25=m[(v-0)/0.2]
5=mv
v=5/m
This velocity acts as initial velocity for the next case.
Case:2
Force of 70N acts for the next 0.1s in Opposite direction.
Initial velocity=5/m
Final velocity=-5 {negative as because in opposite direction}
Force=-70N
F=ma
-70=m[(-5-5/m)/0.1]
-7=m[-5-5/m]
-7=-5m-5
-2=-5m
m=2/5=0.4Kg
Hence mass of the body is 0.4Kg.
Case:1
Force of 25N acts on the body for 0.2s
We know that F=ma
F=ma
F=m[(v-u)/t]
25=m[(v-0)/0.2]
5=mv
v=5/m
This velocity acts as initial velocity for the next case.
Case:2
Force of 70N acts for the next 0.1s in Opposite direction.
Initial velocity=5/m
Final velocity=-5 {negative as because in opposite direction}
Force=-70N
F=ma
-70=m[(-5-5/m)/0.1]
-7=m[-5-5/m]
-7=-5m-5
-2=-5m
m=2/5=0.4Kg
Hence mass of the body is 0.4Kg.
Answered by
39
Answer:
0.4 kgs is the answer for what u have been searching so long
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