Question

A force of 2gf produces a moment of force of 0.75N m. Find the perpendicular distance between the point of application of force amd turning point.(take g= 1000cm/s^2

Answer 1

Answer: 37500 cm (375m)

Explanation:

*Coversion of Force: 2gf = 0.002kgf

*Moment of force = Force x Perpendicular distance(r)

->  0.75  =  0.002 * r

->  r= 0.75/0.002 = 375m = 37500cm

Answer 2

Answer:

37500cm ( 375m)

Explanation:

conversion of Force 2gf = 0.002gf

'Moment' of Force = Force x

perpendicular distancec ( r )

= 0.75 = 0.002 * r

= r = I 0.75 / 0.002 = 375 m = 37500 cm

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