A force of (2i+3j+4k)N acts on a body and produces a displacement of 3i+4j+5k then the amount of work done
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Answer:
We know Power=
time
Workdone
-----(A)
Also work done = Force×displacement------(B)
Work done is the dot product of the vector quantities
W.D=[2
i
^
+3
j
^
+4
k
^
].[3
i
^
+4
j
^
+5
k
^
]
=6+12+20
=38
Substituting the above found value in A
Power=
4
38
=9.5 W
t= 4 seconds (given)
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