Question

A force of 2i+3j+4k n acts on a body for 4 sec and produce a displacement of 3i+4j=5k m.The power used is

Answer 1

power=work done / time

p=F.S/t

f.s=2i+3j+4k . 3i+4j+5k

    = 16+12+20=38

w=38

t=4

p=38/4

   =9.5

Hope this helps u :)

   

Answer 2

The power of the object is 0.5 Watts.

Explanation:

Given that,

Force, $F=(2i+3j+4k)\ N$

Displacement, $d=(3i+4j-5k)\ m$

Time, t = 4 s

To find,

Power used by the body.

Solution,

We know that the power of an object is given by the work done divided by total time taken. It is given by :

$P=\dfrac{W}{t}$

W is the work done,

$W=F{\cdot} d$

$W=(2i+3j+4k) {\cdot} (3i+4j-5k)$

$W=2(3)+3(4)+4(-5)=-2\ J$

Power,

$P=\dfrac{-2\ J}{4\ s}$

P = -0.5 Watts

So, the power of the object is 0.5 Watts.

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