Question

A force of 2N acting on a body changes its velocity from 2m/s to 5m/s in 10s find mass of a body.

Answer 1

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Given that,

=> F = 2 N

=> T = 10 s

=> A = ( v - u ) / t

= ( 5 - 2 ) / 10 = 3 / 10 = 0.3 m/s ^2

S0,

=> F = m x a

=> f = m x 0.3

=> m = 2 / 0.3

=> m = 6.6g

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Answer 2

Given :

• Force (F) = 2 N

• Initial velocity (u) = 2 m/s

• Final velocity (v) = 5 m/s

• Time interval (t) = 10 s

To Find :

• Mass of the body

Solution :

Use 1st equation of motion for calculating value of acceleration :

$\\ \implies \boxed{\rm{v = u + at}} \\ \\ \\ \implies \rm{a = \dfrac{v - u}{t}} \\ \\ \\ \implies \rm{a = \dfrac{5 - 2}{10}} \\ \\ \\ \implies \rm{a = \dfrac{3}{10}} \\ \\ \\ \implies \rm{a = 0.3} \\ \\ \\ \underline {\rm{\therefore \: Acceleration \: of \: body \: is \: 0.3 \: ms^{-2}}}$

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Now, use formula of force

$\implies \boxed{\rm{F = ma}} \\ \\ \\ \implies \rm{m = \dfrac{F}{a}} \\ \\ \\ \implies \rm{m = \dfrac{2}{0.3}} \\ \\ \\ \implies \rm{m = 6.67} \\ \\ \\ \underline {\rm{\therefore \: Mass \: of \: body \: is \: 6.67 \: kg}}$