Question

A force of 2N actnig through a moment arm of √2 and produce torque of √6 what is the angle b/w r and f

Answer 1

Answer:

Torque is basically the cross product of the position vector r (about a point) and the force F acting at that particular point (i.e. the point whose position vector is r)

Here, the position vector r

= position of the point (2,-3,6) with respect to the point 2i - 5j + 3k

= ( 2i - 3j + 6k ) - ( 2i - 5j + 3k )

= 2j + 3k

Force F = i + 2j - 3k

So, Torque (T)

= r * F

Answer 2

Answer:

Your answer is 60°

Explanation:

Torque is cross product of r and F.

So Torque=F*r

Torque=FrSinα

√6=2*√2*Sinα

Sinα=√6÷2√2

Sinα=√3÷2

α=Sin-1(√3÷2)

α=60°