Question

A force of 3 icap + 4 j cap + 5 k cap and acts on a body for 5 seconds produces a displacement 2 i + 3 + 4 k the average power used is

Answer 1

Answer:-

Given:-

F = 3i + 4j + 5k.

S = 2i + 3j + 4k.

time = 5 seconds.

Explanation:-

From velocity formula,

$velocity = \frac{distance}{time}$

Firstly finding the magnitude of Force and displacement.

Force

$|F| = \sqrt{ {3}^{2} } + {4}^{2} + {5}^{2}$

$|F| = \sqrt{25 + 25}$

$|F| = 5 \sqrt{2}$

Displacement

$|S| = \sqrt{ {2}^{2} } + {3 }^{2} + {4}^{2}$

$|S| = \sqrt{4 + 9 + 16}$

$|S| = \sqrt{29}$

Velocity = ?.

$v = \frac{ \sqrt{29} }{5}$

Power

P = Force × velocity

$P = 5 \sqrt{2} \times \frac{ \sqrt{29} }{5}$

$P = \sqrt{2 \times 29}$

$P = \sqrt{58}$

or

$P = 7.61$

$\boxed{\boxed{P = \sqrt{58}watts =7.61watts}}$

So,the Average power of the body is √58watts or 7.61watts .

Answer 2

Answer:

P=7.6

Explanation: