Question

A force of 3 N acts perpendicular to a force of 4 N. Their resultant has a magnitude of

Answer 1

Answer:

HOPE IT HELPS:-)

Explanation:

Answer 2

Answer:

Given:

Magnitude of two forces F₁ = 3N

and F₂ = 4N

Angle between F₁ and F₂ = θ = 90°

To find:

Resultant of two forces.

Solution:

R =

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$\sqrt{ F²₁+ F²₂ + 2F₁F₂ cosθ}$

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We know that cosθ = 0

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So R =

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$\sqrt{F²₁+ F²₂ }$

$\implies R = \sqrt{3 {}^{2} + 4 {}^{2} } \\ \implies R = \sqrt{9 + 16} = \sqrt{25} \\\implies R = 5N$

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Hence magnitude of the resultant force is 5N.