A force of 30 N acts on a body and moves it through a distance of 2 m in the direction of the force. Calculate the work done by the force.
Answers
Question
A force of 30N acts on a body and moves it through a distance of 2 m in the direction of force calculate the work done by the force .
Answer
Force (F) = 30N
Displacement(S) = 2m
Work done = ?
As we know ,
Work done = Force * Displacement
=> F * S
Now ,
Work done = 30N * 2m
Work done = 60 J
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>>Work done = Force multipled by diplacement.
>>Potential energy = pgh
>>Kinetic energy = 1/2mv^2
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Work is said to be done only when the force is applied and taken along(Displacement)
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Answer:
Answer:Answer :-
Answer:Answer :-Force (F) = 30N
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5m
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?As we know ,
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?As we know ,Work done = Force * Displacement
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?As we know ,Work done = Force * Displacement=> F * S
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?As we know ,Work done = Force * Displacement=> F * SNow ,
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?As we know ,Work done = Force * Displacement=> F * SNow ,Work done = 30N * 5m
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?As we know ,Work done = Force * Displacement=> F * SNow ,Work done = 30N * 5mWork done = 150 J
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?As we know ,Work done = Force * Displacement=> F * SNow ,Work done = 30N * 5mWork done = 150 J••••••••••••••••••••••••••••
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?As we know ,Work done = Force * Displacement=> F * SNow ,Work done = 30N * 5mWork done = 150 J••••••••••••••••••••••••••••>>Work done = Force multipled by diplacement.
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?As we know ,Work done = Force * Displacement=> F * SNow ,Work done = 30N * 5mWork done = 150 J••••••••••••••••••••••••••••>>Work done = Force multipled by diplacement.>>Potential energy = pgh
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?As we know ,Work done = Force * Displacement=> F * SNow ,Work done = 30N * 5mWork done = 150 J••••••••••••••••••••••••••••>>Work done = Force multipled by diplacement.>>Potential energy = pgh>>Kinetic energy = 1/2mv^2
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?As we know ,Work done = Force * Displacement=> F * SNow ,Work done = 30N * 5mWork done = 150 J••••••••••••••••••••••••••••>>Work done = Force multipled by diplacement.>>Potential energy = pgh>>Kinetic energy = 1/2mv^2•••••••••••••••••••••••••••••••••••
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?As we know ,Work done = Force * Displacement=> F * SNow ,Work done = 30N * 5mWork done = 150 J••••••••••••••••••••••••••••>>Work done = Force multipled by diplacement.>>Potential energy = pgh>>Kinetic energy = 1/2mv^2•••••••••••••••••••••••••••••••••••Work is said to be done only when the force is applied and taken along(Displacement)
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?As we know ,Work done = Force * Displacement=> F * SNow ,Work done = 30N * 5mWork done = 150 J••••••••••••••••••••••••••••>>Work done = Force multipled by diplacement.>>Potential energy = pgh>>Kinetic energy = 1/2mv^2•••••••••••••••••••••••••••••••••••Work is said to be done only when the force is applied and taken along(Displacement)•••••••••••••••••••••••••••••••••••
Answer:Answer :-Force (F) = 30NDisplacement(S) = 5mWork done = ?As we know ,Work done = Force * Displacement=> F * SNow ,Work done = 30N * 5mWork done = 150 J••••••••••••••••••••••••••••>>Work done = Force multipled by diplacement.>>Potential energy = pgh>>Kinetic energy = 1/2mv^2•••••••••••••••••••••••••••••••••••Work is said to be done only when the force is applied and taken along(Displacement)•••••••••••••••••••••••••••••••••••folow me♥️