Question

a force of 30 n acts on a body and moves it through a distance of 5 m in the direction of force calculate the work done by the force

Answer 1

Answer :-

Given:

⇒ Force (F) = 30 N

⇒ Displacement (s) = 5 m

⇒ Angle b/w force and displacement = 0°

To find:

⇒ Work done (W)

Solution:

⇒ Work done (W) = Force × Displacement × cos theta

• 30 × 5 × cos0°
• 150

∴,

⇒ The work done on the body is 150 J.

Answer 2

Answer:

The work done by the force is 150J.

Explanation:

The force's work is given as,

$W=F.d=Fdcos\theta$      (1)

Where,

W=work done by the force

F=force acting on the body

d=distance moved by the body

θ=angle between force and distance

From the question we have,

The force acting on the body(F)=30N

The distance moved by the body(d)=5m

The angle between the force and distance=0° (as the body moves in the direction of force)

By substituting required entities in equation (1) we get;

$W=30\times 5\times cos0\textdegree$

$W=150\ J$

Hence, the work done by the force is 150J.

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