Question

A force of 30 N acts on an area of 60 cm^2 .what is the pressure in pascal?

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Answer 1

Given:

• Force = 30 N
• Area = 60 cm²

To find :

• Pressure in Pascal

Solution :

Area = 60 cm² = 60 × $\tt 10^{-4}$ m²

The formula for pressure is given by :

$\green{\boxed{ \sf \red{pressure}= \frac{\orange{force}}{ \pink{area}}}}$

$= \tt \dfrac{30}{60 \times {10}^{ - 4} } \\ \\ \tt = \frac{30 \times {10}^{4} }{60}$

$\tt = 0.5 \times 10^4 N/m^2$

= 0.5 × 10⁴ Pa

________________________

$\underline{ \underline{ \mathfrak {\purple{force :}}}}$

• An agent that cause the change in motion, direction or shape of a body is called a force .
• Its SI unit is Newton denoted by N .
• It is a vector quantity .

$\underline{ \underline{ \mathfrak {\blue{Pressure :}}}}$

• The amount of force applied per unit area is called pressure .
• Its SI unit is Pascal denoted by Pa .
• It is also a vector quantity.
• 1 Pascal = 1 Newton/ square metre

Answer 2

$\blue{\bold{\underline{\underline{Given:-}}}}$

• Force = 30 N
• Area = 60 cm²

$\orange{\bold{\underline{\underline{Required \: to \: Find:-}}}}$

• Pressure (Pascal)

Area = 60 cm²

= 60 × 10^(-4) m²

Formula used :

$\huge\bf\green{Pressure = \frac{Force}{Area}}$

$= \frac{30}{60 \times {10}^{ - 4} }$

$= \frac{30 \times {10}^{4} }{60}$

$= \frac{1}{2} \times {10}^{ - 4}$

$= \frac{1}{2} \times {10}^{ - 4} \: N/{m}^{2}$

$= 0.5 \times {10}^{4} \: Pa$

$\bf\blue{Hope\ it\ helps.}$

$\bf\pink{Plz\ Mark\ As\ Brainliest.}$