Question

A force of 30 N acts on an object of mass 500 g at rest for 10 seconds. The final velocity of the object
would be
(1) 60 m/s
(2)6/5 m/s
(3) 15 m/s
(4) 120 m/s​

Answer 1

Step-by-step explanation:

F= ma

a= F/m

= 30N/ 0.5 kg

= 60 m/ s^2

v= u+at

u= o

v= at

v= 60×10=600m/s

I think process is like this .but it is not in your options