Question

a force of 30 N acts on rod of area of cross section 5× 10-6 m² the stress produced in dyne/cm² is ​

Answer 1

Answer:

6*10^7dyne/cm^2

Explanation:

Stress = F/A

Given F =30N =30*10^5dyne

Since 1N =10^5dyne

A =5*10^-6m^2 = 5*10^-6*100*100cm^2

= 5*10^-2cm^2

Stress = 30*10^5/(5*10^-2)

= 6*10^7dyne/cm^2