a force of 30 newton is acting on a body and actor of 60 degree and the body is displayed by 4 metre in horizontal direction calculate the amount of work done
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0
Answer:
Explanation:
given,
force = 5 N
angle formed = 30°
displacement = 6 m
therefore work done ,
= F*s*cosθ
= 5 * 6 * cos (30)
= 30 * 0.866...
= 25.98 J
therefore work done = 25.98 J
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