Question

a force of 30 newton is acting on a body at an angle of 60 degree and the body is displaced by 4 m in horizontal direction. calculate the amount of work done​

Answer 1

$w = fs \cos( \alpha )$

where alpha is the angle between FORCE and DISPLACEMENT

Given.

F = 30N

s =60m

$\alpha = 60$

So, simply substituting the values in the formula

we get

W =

$30 \times 60 \times \cos(60)$

$= 900$

Thus, work done in moving the body = 900J

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