Physics, asked by saniyanaaz3, 1 year ago

a force of 300 Newton acts on A bullet of area of cross section is 0.6 CM square find the pressure on the bullet​

Answers

Answered by WeirdFlexButOk
1

Here's your answer

Force=300N

Area=0.6cm²=6×10^-5m²

Pressure=Thrust or Force/Area

=300/6×10^-5

=50×10^5

Answer==> 5×10^6 pascal

Hope it helps✌


saniyanaaz3: what is this ^
saniyanaaz3: I can't understand
WeirdFlexButOk: ^ this means "raised to the power"
WeirdFlexButOk: 5^2 means 5 square
WeirdFlexButOk: 4^3 means 4 cube
WeirdFlexButOk: and so on
WeirdFlexButOk: hope it helps
saniyanaaz3: ok
saniyanaaz3: yeah yeah really it helps thanks
WeirdFlexButOk: Welcome ✌
Answered by Anonymous
2

Force acted on the cross section of the bullet = 300 Newtons

Area of the cross section of the bullet = 0.6 cm²

We know that the units of area and force should be of the same units. Here given SI units of Force is Newtons, Area CGS units of force is cm². So, we need to convet the the area units into SI units.

= 0.6/10000

= 6/100000 ( To eliminate the decimal in numerators I multiplied both numerator and denominator by 100)

= 6/1000000 m²

Area of cross section of bullet = 6/100000 m²

Pressure on bullet = Force/Area

= 300/(6/100000)

= 300 * 100000/6

= 300 * (10 raised to 5)/6

= 100 * (10 raised to 5)/2

= 50 * 10 raised to 5

= 5 * 10 * 10 raised to 5

= 5 * 10 raised to (5 + 1)

= 5 * 10 raised to 6

Pressure on bullet = 5 * 10 raised to 6 Pascal

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