a force of 300N is acting on a surface of area 3m². If the force is doubled and the area of the surface is made half of the initial area, what would be the difference in the pressure?
Answers
Answered by
2
Answer:
Given, froce=100N
and area=4m
2
∴pressure=
area
force
=
4m
2
100N
=25Pa
Answered by
3
Answer:
75 Pa
Explanation:
Assuming that you're asking for the difference in Initial and final pressure -
Since we know, Pressure = Force / Area
Initially, Force = 100 N and Area = 4 sq. m
therefore, pressure = 25Pa
Finally, Force = 200 N and Area = 2 sq. m
therefore, pressure = 100Pa
Difference between Final and Initial = 100 - 25 = 75Pa
Explanation:
MARK BRAINLIEST
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