Physics, asked by mamatamb, 9 hours ago

a force of 300N is acting on a surface of area 3m². If the force is doubled and the area of the surface is made half of the initial area, what would be the difference in the pressure?​

Answers

Answered by jiakher84
2

Answer:

Given, froce=100N

and area=4m

2

∴pressure=

area

force

=

4m

2

100N

=25Pa

Answered by chauhanreetu673
3

Answer:

75 Pa

Explanation:

Assuming that you're asking for the difference in Initial and final pressure -

Since we know, Pressure = Force / Area

Initially, Force = 100 N and Area = 4 sq. m

therefore, pressure = 25Pa

Finally, Force = 200 N and Area = 2 sq. m

therefore, pressure = 100Pa

Difference between Final and Initial = 100 - 25 = 75Pa

Explanation:

MARK BRAINLIEST

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