Question

A force of 30N acts on a body and moves it through a distance of 5 m in the direction of force calculate the work done by the force ​

Answer 1

$\huge\mathfrak{Question }$ :-

A force of 30N acts on a body and moves it through a distance of 5 m in the direction of force calculate the work done by the force ​.

$\huge\mathfrak{Answer}$:-

Force (F) = 30N

Displacement(S) = 5m

Work done = ?

As we know ,

Work done = Force * Displacement

=> F * S

Now ,

Work done = 30N * 5m

Work done = 150 J

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>>Work done = Force multipled by diplacement.

>>Potential energy = pgh

>>Kinetic energy = 1/2mv^2

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Work is said to be done only when the force is applied and taken along(Displacement)

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Answer 2

$\mathfrak{\huge{\blue{\underline{\underline{AnswEr :}}}}}$

» Total Work Done by Force is $\mathscr\red{150\:Joule}</h3><h3>$

$\mathfrak{\huge{\blue{\underline{\underline{ExplanaTion :}}}}}$

» Given :

✿ Force = 30N

✿ Distance = 5m

» To Find :

• Work Done by the Force

» Solution :

We Know that -

$\large \boxed{Work\: Done = Force \times Displacement}$

⇒ $W \: = F \times S \times \cos(Φ)$

⇒ $W = 30 \times 5 \times \cos(0)$

⇒ $W = 150 \times 1$

$\boxed{\red{Cos(0°)=1}}$

⇒ $W \: = 150 \: joule$

❖ Total Work Done by Force is $\mathscr\green{150\:Joule}</p><p>$

✾ $\boxed{\blue{Note :}}$

» Work Done = Work is the energy spent by a force acting through a distance.

Work = (force) × (displacement) × cos(Φ)

where Φ is the angle between the direction of the force and the displacement.

» Displacement = Displacement is a vector whose length is the shortest distance from the initial to the final position.