Question

A force of 3600 N acts on the surface of area 40 cm^2 normally. What would be the pressure on the surface ?

Answer 1

Answer:

pressure= 9000 pascal

Explanation:

p= f/a

  = 3600/0.40

  =9000 pa

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Answer 2

Given:-

Force=3600N

area=40 cm^2=0.004 m^2

$p = \frac{f}{a}$

$p = \frac{3600}{4 \times {10}^{ - 3} }$

$p = \frac{36 \times {10}^{ 5} }{4}$

$p = 9 \times {10}^{5} pascal$