Question

a force of (3x)N acting on a body of mass 10 kg along the x-axis ,displaces it from x=2m to x=6m the work done by the force is
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Answer 1

Answer:

answer is 48 N

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Answer 2

The work done by the force is 48 J.

The work done by a force is defined as the product of the force and the displacement of the object in the direction of the force. In this case, the force is (3x) N and the displacement is from x = 2 m to x = 6 m along the x-axis. We can calculate the work done by integrating the force with respect to x over the interval [2, 6].

W = ∫(3x) dx from x = 2 to x = 6

W = [3/2 x²] from x = 2 to x = 6

W = (3/2)(6² - 2²)

W = (3/2)(32)

W = 48 J

Therefore, the work done by the force is 48 J.

This result shows that the work done by the force is positive, which means that the force is doing work on the object by transferring energy to it. The amount of work done is proportional to the displacement and the magnitude of the force.
In this case, the force is increasing linearly with the displacement, resulting in a quadratic relationship between work and displacement.

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