Question

A force of 4.0 N acts on a body of mass 2.0 kg for 4.0 s. Assuming the body to be initially at rest, find (a) its velocity when the force stops acting, (b) the distance covered in 10 s after the force starts acting.

Answer 1

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Answer 2

Force = 4 N., Mass = 2 kg.

Using the Formula,

F = ma , a = F/m    a = 4/2

a = 2 m/s²

Now, u = 0

t = 4 seconds

v - u = at

⇒ v - 0 = 2 × 4

⇒ v = 8 m/s.

Now, v² - u² = 2aS

64 = 2 × 2 × S

S = 16 m.

It is the distance covered in first 4 seconds.

Now, for the distance covered in another 6 seconds.

u =  v of above = 8 m/s.

t = 10 - 4 = 6 seconds.

a = 0 [Force is not acting now]

S = ut + 1/2at²

∴ S = 8 × 6 +  0

∴ S = 48 m.

Total distance covered in 10 seconds = 16 + 48 = 64 m.

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