Question

A force of 4.5N acts on a charge of 7.5×10-4C. Calculate the intensity of electric field at that point.

Answer 1

Explanation:

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Answer in the attachment

Answer 2

Given,

force, F = 4.5 N

charge, q = 7.5×10-4C.

To find,

Intensity of electric field at this point

Solution,

Electric field formula is

E = F/q

E = 4.5 / 7.5×10-4

E = 6000

E = 6 × 10³ N/C

The intensity of electric field at the point is 6 × 10³ N/C.