Physics, asked by naziahassan3934, 6 hours ago

A force of 4 N act on a body of mass 2 kg for 4 second .if the initial velocity is zero find its velocity when the force stops acting.

Answers

Answered by Anonymous
4

STEP-BY-STEP EXPLANATION:

.

\longmapsto\sf Force \:  (F) = 4N  \:  \: or \:  \: 4kgm {s}^{ - 2} \\

\longmapsto\sf Mass \: ( M)= 2 kg \\

\longmapsto\sf Initial  \: Velocity \:  (u) = 0 \\

\longmapsto\sf Final \:  Velocity \:  (v) = \:  ? \\

\longmapsto\sf Time  \: Taken \: (t) = 4s \\

As  \: we \:  know  \: that,

\longmapsto\bf F = M.A

\longmapsto\sf 4kgm {s}^{ - 2}  =2kg.A \\

\longmapsto\sf A  =  \frac{ \cancel{4kg} m{s}^{ - 2} }{ \cancel{2kg}} \\

\longmapsto\sf A  =  2 m{s}^{ - 2}  \\

As  \: we \:  know  \: that,

\longmapsto\bf A =  \frac{v - u}{t}   \\

\longmapsto\sf \frac{v -0}{4s}  = 2m {s}^{ - 2}  \\

\longmapsto\sf{v } = 2m {s}^{ - 2} \times 4s  \\

\longmapsto\bf{v } = 8m {s}^{ - 2}   \\  \\

REQUIRED ANSWER,

.

  • The Final Velocity is 8m per second.

Similar questions