Question

. A force of 4 N acts on a body of mass 2 kg for 4 s. Assuming that the body to be initially at rest, find (i) its velocity when the force stops acting (ii) the distance covered in 10 s after the force starts acting. ​

Answer 1

Answer:

force = 4N MASS =2KG HENCE ACCELERATION = 2MS^-2

V =U +AT = 2×4 M^-S = 8

S = 1/2AT^2

= 100 M