Question

A force of 4 N acts on a body of mass 2 kg for 4 sec. If the initial velocity is zero, find its velocity when the force
stops acting.
Ans. 8 ms​

Answer 1

Answer:

v=4x4/2=8

Explanation:

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Answer 2

Given :-

• A force of 4 N acts on a body of mass 2 kg for 4 sec. If the initial velocity is zero.

To find :-

• Velocity when the force

stops acting.

Solution :-

• Force (F) = 4N

• Mass (m) = 2kg

As we know that

→ Force = mass × acceleration

→ F = m × a

→ 4 = 2 × a

→ a = 4/2

→ a = 2m/s²

Hence, acceleration of a body is 2m/s²

Now,

• Initial velocity (u) = 0

• Time taken (t) = 4 sec

According to first equation of motion

→ v = u + at

→ v = 0 + 2 × 4

→ v = 8m/s

• Another method :-

→ F = m(v - u)/t

→ 4 = 2(v - 0)/4

→ 4 = v - 0/2

→ 4 × 2 = v - 0

→ 8 = v

→ v = 8m/s

Therefore,

• Velocity when the force stops acting i.e 8m/s

More to know :-

• s = ut + ½ at² (second equation of motion

• v² = u² + 2as (Third equation of motion)