Question

A force of 4 N acts on a body of mass 2 kg for 4 seconds.
Assuming the object to be initially at rest , find the distance covered in 10 seconds after the force starts acting.

Explain and write all the steps

Answer 1

By Applying Newton's Second Law of Mo

Distance covered by while force is acting:-

S1= (v²-u²)/2a

S1=(8²-0²)/2x2

S1= 16 m

Distance covered while force is not acting:-

S2= ut+1/2at²

So, here will be

u= 8 m/s

t=10s-4s=6 s

a= 0 (no acceleration)

S2= 8x6+1/2 x 0 x 6

S2 = 48 m

So that,

Total distance,

S = S1 + S2

S = (16+48) m = 64 m

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