Question

a force of 4 n acts on a body of mass 2kg for 4s find ( 1 ) its velocity when the force stops acting ( 2 ) the distance covered in 10s after the force starts acting

Answer 1

Answer:

Step-by-step explanation:

formula of force,

$\large{\boxed{\tt f=ma}}$

$\large \tt 4=2×a$

$\large \tt a=2\:m/s^2$

formula of acceleration (a) is,

$\large{\boxed{ \tt a=\dfrac{(v-u)}{t}}}$

$\large \tt 2 = \dfrac{(v-0)}{4}$

$\large \tt v=4×2$

$\large \tt v=8\:m/s$

formula of distance (s),

$\large{\boxed{ \tt s = \dfrac{(v^2-u^2)}{2a}}}$

$\large\tt = \dfrac{8^2}{2×2}$

$\large\tt = \dfrac{64}{4}$

$\large\tt = 6 \: m$